Display Image in website written in C# from url

I am trying to create a website that can let user to search images. I created a local database ( a folder with a few images) for image, and there are 3 columns for data: title, picURL and keyword.

At my default page, I set up a textbox and Search button. What I did is:

string query = "SELECT picURL FROM imagedatabase WHERE [keyword] = '" + keyword + "'";

[keyword] is one of the name of the column and the keyword is the one user types in the textbox.

So now if I find an image in the database, then I got its URL. But how can I display the image in .aspx? like are they any specific command or something I can do开发者_开发百科 to display the image?

thanks

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EDIT:

So I changed the code like this:

In my homepage.aspx, I added in this:

<asp:Image ID="Image1" runat="server" ImageUrl="Image1.ImageUrl" />

and in my homepage.aspx.cs, I wrote this:

  protected void btnImageSearch_Click(object sender, EventArgs e)
{
    ImageSearch();
}
private void ImageSearch()
{
    string ImageURL;
   ImageURL= Process.KeywordSearch(txtSearch.Text);
   Image1.ImageUrl = ImageURL;

}

and in my Process.cs, I wrote this:

public static string KeywordSearch(string keyword)
{
    string query = "SELECT imagepath FROM tbimage WHERE [title] = '" + keyword + "'";       

    return query;

}

After I wrote all these, I tried to debug. I typed in the keyword, but no image showed up. I know in Process.cs, query will get the URL in database (the URL is like C:\ ....) So Image1.ImageUrl should equal to that URL. but then I am wondering if

can this really get the Image1.ImageUrl? because no image showed up.

Hope somebody can help and thanks

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for this you can use Image control of asp.net and set its ImageUrl property to your image url. Like this

<asp:Image ID="Image1" runat="server" />

and in CodeBehind

Image1.ImageUrl = query;

Do as follow

1 Save or move your images into a folder.
2 Add this folder into your solution or project.
3 Take image name only (not physical path) from your database.
4 Set ImageUrl property to virtual path.