I'm trying to pack some unsigned int data into a string buffer created using ctypes.create_string_buffer
.
Here is the following code segment, and a running example showing the error on codepad:
import struct
import ctypes
import binascii
buf = ctypes.create_string_buffer(16)
struct.pack_into("=I=I=I", buf, 0, 1, 2, 3)
print binascii.hexlify(buf)
This yields the 开发者_开发问答following error:
...
struct.error: bad char in struct format
The documentation doesn't allude to whether you can pack data of different types if the underlying buffer is of a specific C type. In this case, trying to pack unsigned int data into a string buffer with an underlying c_char type. Anyone know of a solution to do this, or is there a specific way to create a buffer that can pack any type of data?
You're not supposed to prefix every output specifier with the '=' code. Just say it once:
struct.pack_into("=III", buf, 0, 1, 2, 3)
This yields:
01000000020000000300000000000000
Sorry for resurrecting old topic, but I get the point of "snap" - being hit by probably similar background habit.
"the first character of the format string can be used to indicate the byte order, size and alignment of the packed data" I agree. However:
- Python docs deliberately (?) omit even a single example of use of order formatters (All examples assume a native byte order, size, and alignment with a big-endian machine.)
- One may assume (as I and probably snap did), that "
III
" consists of three format strings and we may format every one of them at will. Hence=I=I=I
. I shot myself in the foot after getting used to Ruby's array.pack, where one may freely change ordering along the expression (Ruby's equivalent isI_I_I_
in this case, as order selector comes after type).
Hence I guess it might be good to add a few lines to struct.pack/unpack docs, giving examples of order & padding use (meh, padding hit me even harder... I could live with native order, but padding ruined my protocol).
Standard operating procedure: Read the error message.
"bad char in struct format" means what it says.
Standard operating procedure: Check the docs. Here it says "the first [my emphasis] character of the format string can be used to indicate the byte order, size and alignment of the packed data" and goes on to list =
as a possibility. The next section (Format Characters) lists many letters including I
.
Conclusion: your format string should be "=III"
.
Note: The problem has nothing to do with the destination buffer at all, let alone its underlying C type:
>>> import struct
>>> struct.pack("=I=I=I", 1, 2, 3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
struct.error: bad char in struct format
>>> struct.pack("=III", 1, 2, 3)
'\x01\x00\x00\x00\x02\x00\x00\x00\x03\x00\x00\x00'
>>>
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