I have this code
template<int N, bool C = true>
struct A;
template<int N>
struct A<N, !(N % 5)> {
/* ... */
};
// should work
A<25> a;
That is, for numbers N
that are divisible by 5
, the compiler should use the partial specialization. But the compiler won't accept that partial specialization, because the Standard requires it to reject such code where a non-type argument of a partial specialization references a parameter and is not simply a parameter (like, A<N, N>
would be valid). But what is the reason of doing so?
Note that I can simply change my code to a more wordy example and it is valid
template<bool> struct wrap;
template<int N, typename = wrap<true> >
struct A;
template<int N>
struct A<N, wrap<!(N % 5)> > {
/* ... */
};
// should work
A<25> a;
This is fine because it's not a non-type parameter anymore. But what is the reason the spec forbids the more straightforward 开发者_如何学Gopartial specialization?
I think a lot of it is historical. Non-type template parameters weren't originally allowed at all. When they were added, there were lots of limitations. As people tried different possibilities, and confirmed that they didn't cause problems, some of the limitations were removed.
Some of those original limitations remain for no particular reason beyond the fact that nobody bothered to work at changing them. Much like there, many of them can be worked around so removing them generally often wouldn't cause any particular difficulty. Mostly it comes down to a question of whether anybody cared enough about this particular case to write a paper about it.
Partial specialisation requires that the non-type template argument be resolvable at compile time.
At this point
template<int N>
struct A<N, !(N % 5)> {
/* ... */
};
N
is a variable that can take more than one value and the compiler is unable to calculate N % 5
with certainty.
Your example instantiates a using
A<25> a;
but you could also have
A<25> a1;
A<15> a2;
How does the compiler choose a value for N in this scenario? It can't and so it has to disallow the code.
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