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C program: Breaking an int into an int array[]

开发者 https://www.devze.com 2023-03-04 20:06 出处:网络
So I\'m working on a Zeller\'s Rule c program, trying to break a 4 digit int that represents the year of a specific date into 2 different int variables containing the first 2 digits and last 2 digits

So I'm working on a Zeller's Rule c program, trying to break a 4 digit int that represents the year of a specific date into 2 different int variables containing the first 2 digits and last 2 digits of said year.

void main()
{
    int day, month, year;
    .
    .
    .
    printf("Enter a Year: ");
    scanf("%i",&year);
    .
    .
    .
    int data, i;    
    int split[3];
    for(i=3 ; i>=0 ; i--)           //Problem is in the loop
    {
        data = year % 10;
        split[i] = data;
        year /= 10; 
        printf("Data%i: %i, should be %i\n", i, split[i], data);
    }
}

The above code outputs: (int year = 1234)

Data3: 0, should be 4
Data2: 0, should be 0
Data1: 0, should be 0
Data0: 0, should be 0

However, if i modify the loop labeled as the problem above as:

int data, i;    
int split[3];
for(i=3 ; i>=0 ; i--)      //Data is all there, correctly
{                          //Problem arises when I try to store to my array
    data = year % 10;
    year /= 10; 
    printf("Data%i: should be %i\n", i, data);
}

output of above code changes: (int year = 1234)

Data3: should be 4
Data2: should be 3
Data1: should be 2
Data0: should be 1

I am completely lost as to why the 开发者_开发问答program 0's out everything as soon as I try to put the data that IS THERE into my array. Been giving me a headache for hours as I obviously have no idea what the problem is.


You have 3 cells in your spit array (int split[3]), but you assign 4 times into it:

for(i=3 ; i>=0 ; i--)

change it to int split[4].

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