Let's say I have a relation r^2 = x^2 + y^2. Now suppose after a calculation i get a complicated output of x and y, but which could in theory be simplified a lot by using the above relation. How do I tell Mathematica to do that?
I'm referring to situations where replacement rules x^2+y^2 -> r^2 and using Simplify/FullSimplify with Assumptions won't work, e.g. if the output is x/y + y/开发者_StackOverflowx = (x^2+y^2)/(xy) = r^2/(xy).
Simplification works really well with built in functions but not with user defined functions! So essentially I would like my functions to be treated like the built in functions!
I believe you are looking for TransformationFunctions.
f = # /. x^2 + y^2 -> r^2 &;
Simplify[x/y + y/x, TransformationFunctions -> {Automatic, f}]
(* Out= r^2/(x y) *)
In the example you give
(x/y + y/x // Together) /. {x^2 + y^2 -> r^2}
==> r^2/(x y)
works. But I've learned that in many occasions replacements like this don't work. A tip I once got was to replace this replacement with one which has a more simpler LHS like: x^2 -> r^2-y^2
(or even x->Sqrt[r^2-y^2]
if you know that the values of x and y allow this).
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