I don't know why this code is not breaking out of the while loop:
int table_size = 953;
store hash_table[953];
for(int i = 开发者_Go百科0; i < table_size; i++)
hash_table[i].count = 0;
//bunch of stuff to get hash value here
while(hash_table[hashNum].data != pString || hash_table[hashNum].count != 0){
hashNum++;
if(hashNum > table_size)
hashNum = 0;
cout << hash_table[hashNum].count;
// to check the value of the count in the array, it IS 0, thus should have broken the loop
}
you probably mean:
while(hash_table[hashNum].data != pString && hash_table[hashNum].count != 0)
In your code the loop will continue if either case is true, hash_table[hashNum].count == 0
is NOT sufficient to make the clause false.
hash_table[hashNum].count
being equal to zero is not sufficient to terminate the loop since you are using ||
("or") between the two conditions in the termination test. If hash_table[hashNum].data
is not equal to pString
then the loop will continue regardless of what hash_table[hashNum].count
is.
I think your loop condition should be on hashNum != 0
instead of hash_table[hashNum].count != 0
.
Secondly, there should be &&
instead of ||
in your while condition.
These are wild guesses since a lot of information is missing in this question.
You should have a look at binary logic, especially De Morgan theorem
!(a && b) is equivalent to (!a) || (!b)
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