making a single script wrapping 3 python codes

I have 3 python codes which I want to call one after another automatically so that they result in the final in s single call. How do I wrap these codes into single script? codes are model-multiple.py, align2d.py, model-single.py.

model-multiple.py is

from modeller import *              # Load s开发者_JS百科tandard Modeller classes
from modeller.automodel import *    # Load the automodel class

log.verbose()    # request verbose output
env = environ()  # create a new MODELLER environment to build this model in


env.io.atom_files_directory = ['.', '../atom_files']

a = automodel(env,
alnfile  = '3NTD_align.ali', # alignment filename
knowns   = ('3NTDA'),    
sequence = 'target',        # code of the target
assess_methods=(assess.DOPE, assess.GA341,assess.normalized_dope))
a.starting_model= 1                 # index of the first model
a.ending_model  = 1              # index of the last model
                                    # (determines how many models to calculate)
a.make()                            # do the actual homology modeling

---

You have two options:

1. The quick-and-dirty way: just call them one after another in a shell script or in a Python script (using system or subprocess.Popen)
2. Make them do their work in some function, import them into a single script and invoke each module's "do work" function

---

If all three scripts are similar to your example, you can use the follow Python script to run them one after the other:

__import__('model-multiple')
import align2d
__import__('model-single')

__import__ is required because hyphens(-) are illegal in import names. If you're willing to rename the scripts:

import model_multiple
import align2d
import model_single

---

You should probably consider organizing your scripts in a way that is convenient for calling both from other scrips and directly. The general pattern is:

def main():
    # do all the work
if __name__ = '__main__':
    import sys
    sys.exit(main())