With the following sql statement I can get all unique values with their counts for a given column:
select column, count(column) as count
from table group by column order by count desc;
How would I get all unique pairs of values with counts. For instance if I had a table of with columns first_name and last_name, I might find results something like this:
first_name | last_name | count
John | Smith | 42
John | Johnson | 39
David | Smith | 37
etc...
Can I do this in basic SQL? I generally use MySQL, but I 开发者_如何学Cassume whatever solution you come up with should be translatable to any db.
You've almost got it correct... You just add an additional GROUP BY
column like so:
SELECT [first_name], [last_name], COUNT(*) AS [Count]
FROM [Table]
GROUP BY [first_name], [last_name]
ORDER BY [Count] DESC;
If you just want the count of how many distinct pairs, you could do this more simply.
A GROUP BY
clause is not necessary.
SELECT COUNT(DISTINCT first_name, last_name) AS count_names FROM Table
Use multiple columns in your group by clause.
select first_name, last_name, count(*) as count from table group by first_name, last_name
SELECT first_name, last_name, COUNT(distinct last_name) AS c
FROM ttable
GROUP BY first_name, last_name
HAVING c > 999
ORDER BY c DESC
Adding distinct will do it in MYSQL. Thanks
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