I am writing a small little script to clear space on my linux everyday via CRON if the cache directory grows too large. Since I am really green at bash scripting, I will need a little bit of help from you linux gurus out there.
Here is basically the logic (pseudo-code)
if ( Drive Space Left < 5GB )
{
change directory to '/home/user/lotsa_cache_files/'
if ( current working开发者_JS百科 directory = '/home/user/lotsa_cache_files/')
{
delete files in /home/user/lotsa_cache_files/
}
}
Getting drive space left
I plan to get the drive space left from the '/dev/sda5' command. If returns the following value to me for your info :
Filesystem 1K-blocks Used Available Use% Mounted on<br>
/dev/sda5 225981844 202987200 11330252 95% /
So a little regex might be necessary to get the '11330252' out of the returned value
A little paranoia
The 'if ( current working directory = /home/user/lotsa_cache_files/)' part is just a defensive mechanism for the paranoia within me. I wanna make sure that I am indeed in '/home/user/lotsa_cache_files/' before I proceed with the delete command which is potentially destructive if the current working directory is not present for some reason.
Deleting files
The deletion of files will be done with the command below instead of the usual rm -f:
find . -name "*" -print | xargs rm
This is due to the inherent inability of linux systems to 'rm' a directory if it contains too many files, as I have learnt in the past.
Just another proposal (comments within code):
FILESYSTEM=/dev/sda1 # or whatever filesystem to monitor
CAPACITY=95 # delete if FS is over 95% of usage
CACHEDIR=/home/user/lotsa_cache_files/
# Proceed if filesystem capacity is over than the value of CAPACITY (using df POSIX syntax)
# using [ instead of [[ for better error handling.
if [ $(df -P $FILESYSTEM | awk '{ gsub("%",""); capacity = $5 }; END { print capacity }') -gt $CAPACITY ]
then
# lets do some secure removal (if $CACHEDIR is empty or is not a directory find will exit
# with error which is quite safe for missruns.):
find "$CACHEDIR" --maxdepth 1 --type f -exec rm -f {} \;
# remove "maxdepth and type" if you want to do a recursive removal of files and dirs
find "$CACHEDIR" -exec rm -f {} \;
fi
Call the script from crontab to do scheduled cleanings
I would do it this way:
# get the available space left on the device
size=$(df -k /dev/sda5 | tail -1 | awk '{print $4}')
# check if the available space is smaller than 5GB (5000000kB)
if (($size<5000000)); then
# find all files under /home/user/lotsa_cache_files and delete them
find /home/user/lotsa_cache_files -name "*" -delete
fi
Here's the script I use to delete old files in a directory to free up space...
#!/bin/bash
#
# prune_dir - prune directory by deleting files if we are low on space
#
DIR=$1
CAPACITY_LIMIT=$2
if [ "$DIR" == "" ]
then
echo "ERROR: directory not specified"
exit 1
fi
if ! cd $DIR
then
echo "ERROR: unable to chdir to directory '$DIR'"
exit 2
fi
if [ "$CAPACITY_LIMIT" == "" ]
then
CAPACITY_LIMIT=95 # default limit
fi
CAPACITY=$(df -k . | awk '{gsub("%",""); capacity=$5}; END {print capacity}')
if [ $CAPACITY -gt $CAPACITY_LIMIT ]
then
#
# Get list of files, oldest first.
# Delete the oldest files until
# we are below the limit. Just
# delete regular files, ignore directories.
#
ls -rt | while read FILE
do
if [ -f $FILE ]
then
if rm -f $FILE
then
echo "Deleted $FILE"
CAPACITY=$(df -k . | awk '{gsub("%",""); capacity=$5}; END {print capacity}')
if [ $CAPACITY -le $CAPACITY_LIMIT ]
then
# we're below the limit, so stop deleting
exit
fi
fi
fi
done
fi
To detect the occupation of a filesystem, I use this :
df -k $FILESYSTEM | tail -1 | awk '{print $5}'
that gives me the occupation percentage of the filesystem, this way, I don't need to compute it :)
If you use bash, you can use the pushd/popd operation to change directory and be sure to be in.
pushd '/home/user/lotsa_cache_files/'
do the stuff
popd
Here's what I do:
while read f; do rm -rf ${f}; done < movies-to-delete.txt
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