I have a PHP script that parses an array using the json_encode() method but returns blank
The PHP Code is as follows
$companies = $db->getCustomerNames();
print_r($companies)
if (!empty($companies)){
$jsonstring = json_encode($companies);
echo $jsonstring ;
}
else{
echo 'false';
}
- $companies is populated and i can print it out yet
I also have a javascript that looks like this
jQuery.ajax({
type: "GET",
url: "http://localhost/myscript.php"
success: function(msg) {
companies = jQuery.parseJSON(msg);
//DO OTHER STUFF WITH companies
}
});
- The PHP script 开发者_运维百科connects to a DB and echo the JSON encoded array
- The Javascript gets the array using AJAX so i can use it's content
- When I hit http://localhost/myscript.php i get a blank page
- Works fine on my local server
- The page is hosted on Yahoo (not sure if it makes a difference)
If the array is displaying like you mention in the text of your question then something is wrong. That page should be displaying something like
["IBM","EDS","MICROSOFT"]
Could you post the relevant PHP code as well please?
Try to use function_exist because on some servers json* functions could be disabled or php is configured to not use it
First you do print_r($companies)
then you do echo $jsonstring;
Remove the print_r line, because ofcourse the response won't be a valid JSON string.
Also try to add header("Content-Type: text/plain");
before you do echo and be sure to put that string before ANY output.
Your js is right and as JohnP said when you hit http://localhost/myscript.php you should get the array displayed as ["IBM","EDS","MICROSOFT"]. Check if you have code similar to the below:
<?php
$a = array (0 =>'IBM' ,1=>'EDS' ,2=>'SUN' ,3=>'GOOGLE' ,4 => 'ORACLE');
echo json_encode($a);
?>
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