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Is there a way of obtaining itemsets from transactions efficiently witho prolog?

开发者 https://www.devze.com 2023-03-03 19:43 出处:网络
I am sorry to ask this question, but it has been a lot since I programmed in Prolog.I think I am used to imperative paradigm.:-(

I am sorry to ask this question, but it has been a lot since I programmed in Prolog. I think I am used to imperative paradigm. :-(

I am trying to obtain itemsets from a Prolog relation:

% transaction(Time, Client, Item)
transaction(1, 2, 10).
transaction(1, 2, 20).
transaction(2, 5, 90).
transaction(3, 2, 30).
transaction(4, 2, 40).
transaction(4, 2, 60).
transaction(4, 2, 70).
transaction(5, 4, 30).
transaction(5, 3, 30).
transaction(5, 3, 50).
transaction(5, 3, 70).
transaction(5, 1, 30).
transaction(6, 1, 90).
transaction(6, 4, 40).
transaction(6, 4, 70).
transaction(7, 4, 90).

% Transformation of transactions to Lists of items per Time per Client.
transaction2(Time, Client, List) :-
    setof(Item, Time^Client^transaction(Time, Client, Item), List).

% Itemsets.
itemsets :-
    transaction(Time, Client, _),
    transaction2(Time, Client, List),
    assert(init(List)).

% Main:
main(Itemsets) :-
    itemsets,
    setof(Basket, init(Basket), Itemsets),
    retractall(init(Basket)).

Then if I consult main(X) I would like to obtain:

X = [[10, 20], [30], [30, 50, 70], [40, 60, 70], [40, 70], [90]]

I just can't figure out a proper way of doing t开发者_如何学Pythonhis.

If I can get a pointer or a little help I will appreciate very much.

Bests,

B.


Try

itemsets(L):-
  setof(Items,
   Time^Client^Item^Nil^(
     transaction(Time, Client, Nil),
     setof(Item, transaction(Time, Client, Item), Items)
    ), L).

and just call itemsets(Itemsets).



main(Items) :-
        findsetof([T1,C1],transaction(T1,C1,_),L1),
        findsetof(L2,(
                    append(_,[[T2,C2]|_],L1),
                    findsetof(Item,transaction(T2,C2,Item),L2)),
                Items).

findsetof(A,B,L) :-
        findall(A,B,C),
        setof(A,member(A,C),L).
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