I have file "sam开发者_StackOverflowple.xml" in my project set as content.
I am running this code:
Uri uri = new Uri("/sample.xml", UriKind.Relative);
StreamResourceInfo contentStream = Application.GetContentStream(uri);
Why it returns null contentStream?
You must set file's Build Action
as Content, and Copy To Output Directory
to Copy Always
or Copy if newer
.
It means probably that it does not find the file. Is the path correct?.
Return Value
Type: System.Windows.Resources.StreamResourceInfo
A StreamResourceInfo that contains a content data file that is located at the specified Uri. If a loose resource is not found, null is returned.
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