I've my mark up below
<div id="loggedIn">
<div id="left-col" class="left">
<div id="nav">
<!-- load later -->
<?php include('file1.php'); ?>
</div>
<div class="clear"></div>
</div>
<div id="right-col" class="left">
<!-- load later -->
<?php include('file2.php'); ?>
</div>
</div>
So I want the page to load the markups first. Then I want to show the ajax loading animated gif image until file1.php
and file2.php
are loaded.
I want to do that in jQuery. I was thinking开发者_开发技巧 of something like $("#nav").load('file1.php');
but when do I fire the event?
Can anyone help me with the jQUery codes??
You could add the image in your div before loading the content via Ajax :
<div id="loggedIn">
<div id="left-col" class="left">
<div id="nav">
<!-- load later -->
<img src="ajaxLoader.gif" id="ajaxLoader1"/>
</div>
<div class="clear"></div>
</div>
<div id="right-col" class="left">
<!-- load later -->
<img src="ajaxLoader.gif" id="ajaxLoader1"/>
</div>
</div>
Then load the content using load()
when the DOM is ready :
$(document).ready(function() {
$("#nav").load("file1.php", function() {
$("#ajaxLoader1").remove();
});
$("#right-col").load("file2.php", function() {
$("#ajaxLoader2").remove();
});
});
This will load the php file in the div, and remove the <img>
when it's done.
jsFiddle example here
You could put your load
calls in a document-ready handler and use its callback to track when something has finished loading:
$(function() {
function done_checker() {
/* See below */
}
// Show loading image here
$('#nav').load('file1.php', done_checker);
$('#right-col').load('file2.php', done_checker);
});
The done_checker
function would wait until both files have loaded and then remove the loading image; see this answer for notes on how to build a done_checker
.
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