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jQuery .ajax request doesn't have any effect

开发者 https://www.devze.com 2023-03-03 15:41 出处:网络
I\'m trying to make a jquery login system, but when I submit the form, the animated gif appears but nothing else.

I'm trying to make a jquery login system, but when I submit the form, the animated gif appears but nothing else.

Here is the code:

$(function(){
    // Quand le formulaire est envoyé
    $('#submit').click(function () {
        // Fade out
        var html = '<div id="head">Connexion en cours...</div>'+
            '<div style="width:100%; text-align: center; margin-top:80px;"><span id="status">Prise de contact avec le serveur</span><span id="img"><br><img src="../img/loaders/bar_blue.gif"></span></div>';
        replaceandfade('#center',html, 10);
                $('#user').attr("disabled", true); 
                $('#pswd').attr("disabled", true); 
                var user = $('#user').val();
                var pswd = $('#pswd').val();
                // On envoie les infos de connexion
                $.ajax({
                    type: "POST",
        开发者_开发问答            url: "ajax_login.php",
                    data: "user=bob&pswd=bob",
                    contentType: "application/json; charset=utf-8",
                    dataType: "json",
                    success: function(data) {
                        $("#status").html("En attente de la réponse");
                        alert(data);
                        if(data.login == "failed"){
                            $("#img").html('');
                            $("#status").html("Le nom d'utilisateur ou le mot de passe saisie est invalide");
                        } else if(data.login == "success"){
                            $("#status").html("Connexion aprouvé, un instant...");
                        } else {
                            $("#status").html("Une erreur est survenu.");
                        };
                    }
                });
    });// END OF #submit.click
}) // END OF onload

The ajax_login.php page returns: {"login":"failed"}

But for now it doesn't do anything.

replaceandfade function

function replaceandfade(div, content, sec) {
    setTimeout(function() {
        $(div).fadeOut("fast", function() {
            $(div).html(content);
            $(div).fadeIn("fast", function() {});
        });
    }, sec)
}


Your request doesn't handle the error outcome, and so if the request fails (for example the server could not be found, or more likely the response is a 500 server error), then nothing will happen.

You can add a error handler using the error function, for example:

$.ajax({
    // Other parameters
    success: function(data) {
        alert(data);
    }, 
    error: function(jqXHR, textStatus, errorThrown) {
        alert("Request failed");
    }
});

Alternatively (or additionally) you can use the complete function to specify actions that should happen when the request ends, be it with a success or fail outcome.

See the documentation for more information.

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