Hello everyone I will be explaining what i need to do and what i have 开发者_如何学JAVAso far.Ok this is what I have to do... Show code that has a div width of 300px and a background color of yellow. Do not display the div by default. Create a show link (a href). Using onclick event handler, show the div area. and this is what I have...
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" >
<html xmlns = "http://www.w3.org/1999/xhtml"xml: lang = "en"lang = "en" >
<head>
<meta http - equiv = "content-type"content = "text/html; charset=utf-8" / >
<link rel="stylesheet: href="finalpart3.css" type="text/css" />
<html>
<head>
<title>Final part 3</title>
<script language="JavaScript">
function setVisibility(id, visibility) {
document.getElementById(id).style.display = visibility;
}
</script>
</head>
<body >
<div id="sub3"><a href="finalpart3.css"><input type="button" name="type" value='Show Layer' onclick="setVisibility('sub3', 'inline');";></div>
</body>
</html>
and here is my css file..
div {
position: absolute;
left: 100px;
top: 200px;
background-color: #FFDD00;
width: 300px;
padding: 10px;
color: black;
display: none;
}
I know my code is wrong somewhere when you click the link it gives the code but no background color or nothing.My brain is fried at this point in time and I know it is something that is small. Can someone might point out where i need an extra code or something so that way the back ground can show up thanks. Or maybe I am ready it wrong and dont need a background color of yellow and 300px in width.
Do you see your typo here?
<link rel="stylesheet: href=...
: !== " for the closing quote.
I'm not really sure what you want to display, but other than epascarello mentioned. There other things you may want to consider. If the <div id="sub3"> is properly link to the css, your link will not be visible. Also I don't know the purpose of this <a href="finalpart3.css".
Here's my modified version of your div check it out if can be a help
<div id="sub3"><a href="finalpart3.css">link</a></div>
<input type=button name=type value='Show Layer' onclick="setVisibility('sub3', 'inline');">
![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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