php preg_replace string extract

Original regexp:

$str = '"foo" <bar@baz.com>';
preg_replace('/\s(<.*?>)|"/', '', $str);

I would like to extract the following:

"foo" <bar@baz.com> extract only => foo
<bar@baz.com>       extract only => <bar@baz.com>
"" <bar@baz.com>    extract 开发者_Python百科only => <bar@baz.com>

Thanks

---

Okay, so it looks like you are wanting to get a value, rather than replace a value, so you should be using preg_match, not preg_replace (though technically you could use preg_replace in a round-about way...)

preg_match('~(?:"([^"]*)")?\s*(.*)~',$str,$match);
$var = ($match[1])? $match[1] : $match[2];

---

You need to require something inside the quotes when you do the replace.

$str = '"foo" <bar@baz.com>';
preg_replace('/"([^"]+)"\s(<.*?>)/', '$1', $str);
preg_replace('/""\s(<.*?>)/', '$1', $str);

Try that. It should leave the address alone if there's no quoted name before it.

Edit: Based on your new example inputs and outputs, try this:

$str = '"foo" <bar@baz.com>';
preg_replace('/"([^"]+)"\s(<.*?>)/', '$1', $str);
preg_replace('/(?:""\s)?(<.*?>)/', '$1', $str);

It should have the following input/output results:

"foo" <bar@baz.com>  -> foo
"" <bar@baz.com>     -> <bar@baz.com>
<bar@baz.com>        -> <bar@baz.com>