I'm working on making a small app/script for putting my mp3's in a folder hierarchy the way I want it, as I haven't found a solution for Unix that is just quite right. So I decided to work on my own. This is an excerpt
if musfile[0]:
m = musfile[0]
tag.link(m)
mar = str(tag.getArtist())
mal = str(tag.getAlbum())
mti = str(tag.getTitle())
#m1track = str(tag.getTrack())
os.rename(m,mar + ' - ' + mti + '.mp3')
m = mar + ' - ' + mti + '.mp3'
os.makedirs(newmusicdir + '/' + mar + '/' + mal + '/')
shutil.copy(m,newmusicdir + '/' + mar + '/' + mal + '/')
if musfile[1]:
m = musfile[1]
tag.link(m)
mar = str(tag.getArtist())
mal = str(tag.getAlbum())
mti = str(tag.getTitle())
#m1track = str(tag.getTrack())
os.rename(m,mar + ' - ' + mti + '.mp3')
m = mar + ' - ' + mti + '.mp3'
os.makedirs(newmusicdir + '/' + mar + '/' + mal + '/')
shutil.copy(m,newmusicdir + '/' + mar + '/' + mal + '/')
And so on. However, in order to organize more than one file, I have been just reusing blocks of code. However, this is extremely inefficient for several blocks of code. For example, if I wanted to organize just 50 songs with my method, I would have over 500 lines of code, for something so simple. So I was wondering if there is 开发者_如何转开发anyway I could use loops. However, the problem with using loops is that with each block I must change the number in the list. For example, from block one to two, I must change musfile[0]
to musfile[1]
, and I do not know how to do that with loops. In fact I have little knowledge about loops. Am I clear enough?
import os, os.path
import shutil
for m in musfile:
tag.link(m)
mar = str(tag.getArtist())
mal = str(tag.getAlbum())
mti = str(tag.getTitle())
new_name = mar + ' - ' + mti + '.mp3'
os.rename(m, new_name)
new_dir = os.path.join(newmusicdir, mar, mal) #use os.path.join instead of +'/' to be more multi platform, it is a good habit
try:
os.makedirs(new_dir)
except:
pass
shutil.copy(new_name, new_dir)
This doesn't answer your original question, but here's my solution to a similar problem: Importer
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