Android - How to exit an app when user press the home button?

I want to know how to exit an app when user press the Home Button.

As far as i know that Home Button moves the running app in background and puts Launcher process in front.

I know i can use finish() but i don't know where i should call it because i have no idea which function is going to get a call when user will press the Home Key.

Than开发者_如何学编程ks.

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Depending on what you want to do, overriding onUserLeaveHint might be the best bet:

http://developer.android.com/reference/android/app/Activity.html#onUserLeaveHint()

This will let your app know that your app is being exited because the user chose to switch apps (Like by hitting the Home button or selecting a notification). This hint function will not be called if an incoming phone call (or similar) is causing your app to go to the background, as the user didn't initiate that action.

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In my case,

I have many activities in application so if I use 'onUserLeaveHint', 'onStop' or ...

It just catch activity transition.

So I put below code every activities. And finally catch user's home button action.

first, you have singleton object

public class ActivityContext {
    public static Context context = null;
}

and every activities,

@Override
protected void onStop(){  //onStop runs after New one's onResume
    super.onStop();
    if(ActivityContext.context==context) { //user home button out
        AppStartEnd.sendAppEndData(context);
    }
}
@Override
protected void onResume(){  
    super.onResume();
    ActivityContext.context = YourActivity.this;
}

I hope this will help you