How to return a string from the function:
char * temp;
int main()
{
temp = malloc(129);
double g_symbol_b_amount = 8536.700000;
printf("\n value: %s\t ", format_double_trans开发者_如何学编程_amount(double g_symbol_b_amount));
}
char *format_double_trans_amount(double amount)
{
char amount_array_n1[25];
strcpy(amount_array_n, "");
sprintf(amount_array_n, "%1f", amount);
temp = amount_array_n;
return temp;
}
Here I got the value: 0.000000
I need the orginal value, please help me on this?I've tested the code below and it behaves correctly. Can you please confirm.
#include "stdio.h"
#include "stdlib.h"
char * temp;
char *format_double_trans_amount(double amount)
{
sprintf(temp,"%1f",amount);
return temp;
}
int main()
{
double g_symbol_b_amount = 8536.700000;
temp = (char*) malloc( sizeof(char) * 129);
printf("\n value: %s\n", format_double_trans_amount(g_symbol_b_amount));
free(temp);
}
Your printf()
format string should have %s
instead of %f
because the value being passed (the value returned from format_double_trans_amount
) is a char *
and not a double
.
I think you should also change your format_double_trans_amount()
function to:
char *format_double_trans_amount(double amount)
{
sprintf(temp,"%1f",amount);
return temp;
}
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