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Passing a non dynamic 2 dimensional array into a function in C?

开发者 https://www.devze.com 2023-03-01 15:57 出处:网络
How do you pass two dimensional arrays into a function? When I pass it, it shows up in the visual studio debugger as a single dimensional array.

How do you pass two dimensional arrays into a function?

When I pass it, it shows up in the visual studio debugger as a single dimensional array. The problem was that when I index sel_col[i], it gets the next character, instead of the next word.

Here is my function prototype:

void print_row(char sel_col[MAX_IDENT_LEN][MAX_IDENT_LEN]);

And here is the definition of my 2d array, and where I call it:

char sel_col[MAX_NUM_COL][MAX_IDENT_LEN];
print_row(sel_col); 
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Solution 1: Remove the first size identifier. Didn't work.

void print_row(char sel_col[][MAX_IDENT_LEN]);

Solution 2: Pass it by reference into the function. Didn't work.

    print_row(&sel_col); 

Solution 3: Use double pointers. I don't want to go this route, since I would rewrite most of my code.


In C, two-dimensional arrays look like one dimensional arrays; a char[3][3] is really a single-dimension array just 9 elements long, and the compiler performs some math to turn two smaller indices into one bigger one. Your function prototype looks correct. What was the problem? Were you getting a compiler error?

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