Question about reversed lists in Python

I am very new to python, as you will be ab开发者_运维技巧le to tell.

If I have a list:

a = [1,2,3,2,1]

This evaluates to true:

a == a[::-1]

...but this evaluates to false:

a == a.reverse()

Why is that the case?

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because .reverse() reverses the list in-place and returns none:

>>> print a.reverse()
None

and a == None evaluates to False.

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a.reverse() has no return value, so the comparison is a==None which is false

you can check with:

>>> str(a.reversed())
'None'

even better:

>>> (id(a.reverse()), id(None))

you'll see the same addresses

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If you want a new copy of the list, use reversed() instead.

a == list(reversed(a))