I'm trying to set up a json example using symfony2.
I've created a test bundle, a test entity ("Message"), set up the orm etc The Message (table) has the following columns: id, title, text I'm trying to expose a route */mydomain/message that would expose a json interface to messages table (a small list)The first methodology I tried was:
Create a MessageController class that uses Symfony\Component\HttpFoundation\Response
and has a function like this:
public function testAction() {
$response = new Response(json_encode(**code_req_here**));
return $response;
}
and set a route like so:
test:
pattern: /test
defaults: { _controller: myProjectmyTestBundle:Message:test, _format: json}
requirements: { _format: (xml|json), _method: GET }
- is this a correct methodology?
- what do I put on the
code_req_here
?
the second methodology I tried was by using the FOS/RestBundle but di开发者_如何学Godn't manage to complete the guide correctly as I understand, so
- please provide a small guide on how to do (just) this with FOS/RestBundle
is this a correct methodology?
Yes I like it but I would modify the routing rule a bit like this:
test:
pattern: /test.{_format}
defaults: { _controller: myProjectmyTestBundle:Message:test, _format: json}
requirements: { _format: (xml|json), _method: GET }
what do I put on the code_req_here?
Put the array that you want to convert to json format. ex. array(array('id' => 1, 'value' => 'test'), array('id' => 2, 'value' => 'smart'))
I recommend using
http://jmsyst.com/bundles/JMSSerializerBundle
$serializer = $container->get('jms_serializer');
$serializer->serialize($data, 'json'); // json|xml|yml
$data = $serializer->deserialize($inputStr, $typeName, $format);
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