I would just like to be able to dynamically write the contents of an xml file from another xml file.
A.XML contains:
<?xml version="1.0"?>
<node>
-Include Contents of b.xml
</node>
B.XML contains:
<anode>
a
</anode>
is there any way to do this in xml?
End product looks like this:
&开发者_JAVA百科lt;?xml version="1.0"?>
<node>
<anode>
a
</anode>
</node>
Update from comments:
In xml alone. so that when i view the xml file in a browser it renders correctly
Use an external (parsed) general entity to reference b.xml
from a.xml
.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE node [
<!ENTITY b SYSTEM "b.xml">
]>
<node>
&b;
</node>
The XML parser will dynamically include the content of b.xml
as it parsees a.xml
and will produce the XML that you want.
If you load a.xml
in IE, it will render correctly.
Note: Some browsers have very strict security policies that cause problems loading referenced XML files from the filesystem and expanding entity references, so it may not work in all browsers if you load a.xml
from the filesystem, but may work in more browsers if you load from a URL.
When this XML document is opened in a browser:
<?xml-stylesheet type="text/xsl" href="stylesheet.xsl"?>
<node>
-Include Contents of b.xml
</node>
With this XSLT stylesheet (other XML document) refered with stylesheet.xsl
relative URI:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="node">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:copy-of select="document('B.xml')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It's rendered (without any style, or with browser default XML stylesheet) as:
<node>
<anode>a</anode>
</node>
Note: The processing instruction. I have used xsl:copy-of
instruction because I didn't want to confuse you with posible infinite recursion...
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