I am using boosthread to create 3 threads calling the same function each time wi开发者_开发技巧th different arguments being passed. E.g. 1/ thread.add(function, int a1, std::string b), thread.add(function, int a2, std::string b), thread.add(function, int a3, std::string b), thread.add(function, int a4, std::string b)
When a global value within the thread is changed I do not want the other threads to execute and change the value again E.g function(a,b){
if(something happened for that thread) value = 5;
//if nothing happened value = 1; }
If one thread gets a value of 5 then I do not want the other threads to interfere with that value and make it go back to 1. How can I do this? Thanks.
Maybe the way to do this is to use boost:mutex but I do not see any gain in doing so because this value is found just before the return statement and I might well have used boost join_all(). But this would be less efficient.
I have one example that will help you. It uses C++11 but can be transposed to Boost easily.
the algorithm is simple, it is made of two main parts:
- Launches three threads
- Joins them(waits for them to finish)
What each thread does:
- Does some work
- Inititalizes a variable if it has never been initialized before (FirstThreadToFinish)
How does the unique intializer function works. 1.uses a mutex to prevent multiple access to shared variables (guarantees that ths function is only acceesed by one thread at a time) 2.If the variables has not been initialized it initializes it with the name of the thread and sets the boolean to true (variable initialized) 3. otherwise does nothing
#include "stdafx.h"
#include <thread>
#include <chrono>
#include <mutex>
#include <iostream>
#include <string>
using namespace std;
mutex m;//to synchronize the data properly
string FirstThreadToFinish;
bool IsInitialized;
//This function is called by the main thread: does the work and initializes the variable only once
int MyThreadFunction(int Duration, const string & ThreadName);
//this function does some work (put here what your thread is really supposed to do)
int DoSomeWork(int Duration);
//this function initializes the variable only once and does nothing otherwise
int InitializeVariableOnce(int Duration, const string & ThreadName);
//this function initializes the variable only once and does nothing otherwise
int InitializeVariableOnce(int Duration, const string & ThreadName)
{
std::lock_guard<mutex> l(m);
if (!IsInitialized)
{
FirstThreadToFinish=ThreadName;
IsInitialized=true;
cout<<"FirstThreadToFinish= "<<ThreadName<< ", IsInitialized= "<<IsInitialized<<endl;
}
return 0;
}
//this function does some work (put here what your thread is really supposed to do)
int DoSomeWork(int Duration)
{
std::this_thread::sleep_for(std::chrono::seconds(Duration));
return 0;
}
int MyThreadFunction(int Duration, const string & ThreadName)
{
DoSomeWork(Duration);
InitializeVariableOnce(Duration, ThreadName);
return 0;
}
int main()
{
//at the begining nothing is initialized
FirstThreadToFinish="Uninitialized";
IsInitialized=false;
cout<< "FirstThreadToFinish= "<<FirstThreadToFinish << ", IsInitalized="<<IsInitialized<<endl;
cout<<"Now launching 3 threads= "<<endl;
thread MyAThread(MyThreadFunction,1,"AThread");
thread MyBThread(MyThreadFunction,2,"BThread");
thread MyCThread(MyThreadFunction,3,"CThread");
MyAThread.join();
MyBThread.join();
MyCThread.join();
return 0;
}
Hope that helps, feel free to tell me if does not answer the question
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