с++ question new delete

I have the following code

void foo()
{
    char* pcBlock = new char[1000];
    ...
    delete[] pcBl开发者_开发百科ock;
    ...
    pcBlock = new char[100000];
    ...
    delete[] pcBlock;
}

Would the code below result in a memory leak?

void foo()
{
    char* pcBlock = new char[1000];
    ...
    pcBlock = new char[100000];
    ...
    delete[] pcBlock;
}

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Yes, there's likely a memory leak if you don't delete[] pcBlock in the first .... Reassigning a pointer does not automatically delete what it previously pointed to.

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Operator "new" and "delete" should be used in pairs. Otherwise, using "new" without "deleting" causes memory leakage.

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Yes, the previously allocated 1000 bytes are not freed and pcBlock is replaced with new set of memory. There is no way to release the previous 1000 bytes. So its a mem leak.

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Yes, it will most likely leak memory (unless the compiler is smart enough to fix that for you, but most won't).

Maybe you should try to realloc in some way.

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Yes, it will. Probably you think that the arrays will overlap and delete therefore will free the first array, but in fact they are allocated to different parts of memory.

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YES IT WOULD CAUSE MEMORY LEAK

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In C++ there is one simple rule: Every call of new should end with call of delete at the end. And every new[] -> with delete[]. Otherwise you will get memory leak. C++ is language where programmer should control dynamic memory by himself (or using 3rd-party libs).