PHP: Use function outside current function

can I use a function that is outside the current function?

eg.

function one($test){
return 1;
}
function two($id){
one($id);
}

Seems like i cant, how should I do i开发者_JS百科t then to use the function that are outside? Thanks

The function is in the same file.. /

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Is your function inside of a class? In that case you have to use $this->function() instead of function().

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That's perfectly valid. Check out the running code here.

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Your code looks valid to me : you are declaring two functions, called one and two ; and two is calling one.

Then, you can call any of those functions, to execute it.

For example, if you execute the following portion of code :

function one($test){
    var_dump(__FUNCTION__);
    return 1;
}
function two($id){
    var_dump(__FUNCTION__);
    one($id);
}

two('plop');

Note that I called two, in the last line of this example.

You'll get this kind of output :

string 'two' (length=3)

string 'one' (length=3)

Which shows that both functions were executed.

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That works fine. However, one ignores its parameter. Then, two ignores the return value from one.

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This should work fine Example:

<?php
function test ($asd)
{
    return $asd;
}
function run ()
{
    return test('dd');
}

echo run();
?>

Maybe you have an issue elsewhere?