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overriding the jquery.param function

开发者 https://www.devze.com 2023-02-28 21:00 出处:网络
I have a problem with the jQuery.param function. jQuery uses + instead of %20 to URL-encode spaces var obje = {

I have a problem with the jQuery.param function. jQuery uses + instead of %20 to URL-encode spaces

var obje = {
    'test': 'tester 2'
}
console.log($.param(obje));

returns "test开发者_如何学C=tester+2"

so I thought about overriding this core function:

(function($){
        $.fn.param = function( a, traditional ) {
            console.log('custom $.param');
            var s = [],
                add = function( key, value ) {
                    // If value is a function, invoke it and return its value
                    value = jQuery.isFunction( value ) ? value() : value;
                    s[ s.length ] = encodeURIComponent( key ) + "=" + encodeURIComponent( value );
                };

            // Set traditional to true for jQuery <= 1.3.2 behavior.
            if ( traditional === undefined ) {
                traditional = jQuery.ajaxSettings.traditional;
            }

            // If an array was passed in, assume that it is an array of form elements.
            if ( jQuery.isArray( a ) || ( a.jquery && !jQuery.isPlainObject( a ) ) ) {
                // Serialize the form elements
                jQuery.each( a, function() {
                    add( this.name, this.value );
                } );

            } else {
                // If traditional, encode the "old" way (the way 1.3.2 or older
                // did it), otherwise encode params recursively.
                for ( var prefix in a ) {
                    buildParams( prefix, a[ prefix ], traditional, add );
                }
            }
            return s.join("&");
            // Return the resulting serialization
            //return s.join( "&" ).replace( r20, "+" );
        };
    })(jQuery);
var obje = {
    'test': 'tester 2'
}
console.log($.param(obje));

This fails however.. The $.param isn't overridden.

Any idea what can be wrong?

Thanks!

Edit: my solution (because I'm a new user I appearently may not answer my own question in 8 hours (Why is that?))

With the solution of ThiefMaster I still had the problem that buildParams is undefined. I solved this by calling the old function and then replacing the + back to %20

// modification of the jQuery.param function: spaces are encoded by jQuery.param with + instead of %20. replace these back to %20
(function($, oldFunction){
    $.param = function( a, traditional ) {
        var s = oldFunction.apply(oldFunction,[a,traditional]);
        // Return the resulting serialization
        return s.replace( '+', '%20' );
    };
})(jQuery,jQuery.param);


You need to use $.param instead of $.fn.param (which would be a function to call on a jQuery object, e.g. $(...).param()).


Old post I know, but for the sake of recorded knowledge. To replace the '+' left behind when using $.param(), consider doing the following:

(Using the code you provided)

var obje = {
'test': 'tester 2'
}
console.log($.param(obje).replace(/\+/g, "%20"));

That will result in: test = tester 2

Hope this helps someone.


The "re-replace" fix may also be implemented by using "beforeSend" in the ajax settings object:

{ beforeSend: function (request, settings) { settings.data = settings.data.replace(/\+/g, "%20"); } }

This approach is suitable for cases where you don't actually want to alter $.param()'s original behavior (for example, if you want "+" in URLs but "%20" for POST data).

[Edited because I remembered that string.replace() will only match once unless it's a regex object with the g flag.]

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