Python Zip-File, wildcards

I was wondering how I could tell Python to extract only ".txt" files from a zip folder, 开发者_如何学Gousing a wildcard. This code works fine for me:

extractor.extract("\websitefiles\test.hmtl")"

How can I use this same code to extract all .txt files in that current directory? I was thinking something like this:

extractor.extract(".*.txt")

but it failed to work.. Any ideas???

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First, you need the file names list, using namelist(). Then, you can filter the "*.txt" files with txtfiles = fnmatch.filter(fn_list,"*.txt") Now you can extract the files one by one:

extracts = [ extractor.extract(txt) for txt in txtfiles ]

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I just need python to extract .txt files in the current directory, that are no larger than 3 megabytes.

#!/usr/bin/env python
import zipfile
from contextlib import closing

MiB = 2**20 # mebibyte

with closing(zipfile.ZipFile("example.zip")) as zfile:
    for info in zfile.infolist():
        if info.filename.endswith('.txt') and 0 < info.file_size <= 3*MiB:
            zfile.extract(info)

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You would need to get the listing of all the files in the ZIP, then ask for each one, one at a time. Zipfile has the namelist() method to give you that list.

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Use the function namelist() to get the names of the files. Then select the txt files from the list and extract them one by one.