I need to create a new table in oracle with only the most current date for each record (开发者_如何学编程step 1), and calculate days between (step 2).
Your suggestions are greatly appreciated:)))
Step 1: First I need to find the max (Mod_date) for each record from table USERS.
TABLE: USERS
Name................Mod_Date
Jason Martin....... 25-JUL-89
Al Mathews......... 21-MAR-89
James Smith........ 12-DEC-88
Robert Black....... 15-JAN-84
Jason Martin....... 25-JUL-99
Al Mathews......... 21-MAR-96
James Smith........ 12-DEC-98
Robert Black....... 15-JAN-94
*TABLE_DESIRED_RESULTS_step1
Name............... Max(Mod_Date)
Jason Martin....... 25-JUL-99
Al Mathews......... 21-MAR-96
James Smith........12-DEC-98
Robert Black.......15-JAN-94
Step 2: Calculate “Number of Days Between Regist_Date and Mod_Date” & add it to the table.
TABLE: REGISTRATION
Name................Regist_Date
Jason Martin.........20-JUL-99
Al Mathews...........23-MAR-96
Robert Black.........20-JAN-94
*TABLE_DESIRED_RESULTS_step2
Name...............Max(Mod_Date).....Number of Days Between Regist_Date and Mod_Date
Jason Martin...... 25-JUL-99..........5
Al Mathews........ 21-MAR-96.........-2
James Smith....... 12-DEC-98..........null
Robert Black...... 15-JAN-94..........-5
*Please note, this data is made up and I already have existing unions and joins to which I have to add this logic. Thanks and have a nice day!
here is my updated answer with a sample.
The important thing is that your date column have the DATE
type.
Here is the tables and data following your specification.
CREATE TABLE USERS
(
ID_USER NUMBER(6) NOT NULL,
NAME VARCHAR2(64) NOT NULL,
MOD_DATE DATE NOT NULL,
CONSTRAINT PK_user PRIMARY KEY (ID_USER)
) ;
INSERT INTO USERS VALUES (1,'Jason Martin',TO_DATE('25-07-1989','DD-MM-YYYY'));
INSERT INTO USERS VALUES (2,'Al Mathews',TO_DATE('21-03-1989','DD-MM-YYYY'));
INSERT INTO USERS VALUES (3,'James Smith',TO_DATE('12-12-1988','DD-MM-YYYY'));
INSERT INTO USERS VALUES (4,'Robert Black',TO_DATE('15-01-1984','DD-MM-YYYY'));
INSERT INTO USERS VALUES (5,'Jason Martin',TO_DATE('25-07-1999','DD-MM-YYYY'));
INSERT INTO USERS VALUES (6,'Al Mathews',TO_DATE('21-03-1996','DD-MM-YYYY'));
INSERT INTO USERS VALUES (7,'James Smith',TO_DATE('12-12-1998','DD-MM-YYYY'));
INSERT INTO USERS VALUES (8,'Robert Black',TO_DATE('15-01-1994','DD-MM-YYYY'));
CREATE TABLE REGISTRATION
(
ID_REG NUMBER(6) NOT NULL,
NAME VARCHAR2(64) NOT NULL,
REGIST_DATE DATE NOT NULL,
CONSTRAINT PK_reg PRIMARY KEY (ID_REG)
) ;
INSERT INTO REGISTRATION VALUES (1,'Jason Martin',TO_DATE('20-07-1999','DD-MM-YYYY'));
INSERT INTO REGISTRATION VALUES (2,'Al Mathews',TO_DATE('23-03-1996','DD-MM-YYYY'));
INSERT INTO REGISTRATION VALUES (3,'Robert Black',TO_DATE('20-01-1994','DD-MM-YYYY'));
First step
CREATE TABLE TABLE_DESIRED_RESULTS_step1
AS (
SELECT
u.NAME
, max(u.MOD_DATE) as "maxi"
FROM USERS u
GROUP BY u.NAME);
second step
CREATE TABLE TABLE_DESIRED_RESULTS_step2
AS (
SELECT
t.NAME
,t."maxi"
, (t."maxi" - r.REGIST_DATE ) as "Nbdays bw RegD and Mod_D"
FROM TABLE_DESIRED_RESULTS_step1 t LEFT OUTER JOIN REGISTRATION r
ON t.NAME = r.NAME);
The trick here is that LEFT OUTER JOIN
allows null value if there is no match with the join.
But there is a database design concern for me. If you have 2 users with the exact same name , you will merge 2 persons in one. Here a solution using IDs and doing the join on the IDs.
CREATE TABLE USERS
(
ID_USER NUMBER(6) NOT NULL,
NAME VARCHAR2(64) NOT NULL,
CONSTRAINT PK_user PRIMARY KEY (ID_USER)
) ;
CREATE TABLE MOD_USERS
(
ID_MOD NUMBER(6) NOT NULL,
ID_USER NUMBER(6) NOT NULL,
CONSTRAINT PK_usermod PRIMARY KEY (ID_MOD)
) ;
ALTER TABLE MOD_USERS ADD (
CONSTRAINT FK_user_mod
FOREIGN KEY (ID_USER)
REFERENCES USERS (ID_USER));
CREATE TABLE REGISTRATION
(
ID_REG NUMBER(6) NOT NULL,
ID_USER VARCHAR2(64) NOT NULL,
REGIST_DATE DATE NOT NULL,
CONSTRAINT PK_reg PRIMARY KEY (ID_REG)
) ;
ALTER TABLE REGISTRATION ADD (
CONSTRAINT FK_user_reg
FOREIGN KEY (ID_USER)
REFERENCES USERS (ID_USER))
;
First step
CREATE TABLE TABLE_DESIRED_RESULTS_step1
AS (
SELECT
m.ID_USER , u.NAME
, max(u.MOD_DATE) as "maxi"
FROM USERS u INNER JOIN MOD_USERS m
ON u.ID_USER = m.ID_USER
GROUP BY m.ID_USER , u.NAME);
second step
CREATE TABLE TABLE_DESIRED_RESULTS_step2
AS (
SELECT
t.ID_USER , t.NAME
,t."maxi"
, (t."maxi" - r.REGIST_DATE ) as "Nbdays bw RegD and Mod_D"
FROM TABLE_DESIRED_RESULTS_step1 t LEFT OUTER JOIN REGISTRATION r
ON t.ID_USER = r.ID_USER);
精彩评论