XQuery error when doing a xslt transform

I have a working style-sheet that works fine with saxon.Now I am using simple XQuery:

transform:transform($xmlNode, $xslNode, ()),  

to do the same thing, it always complains about a syntax in my style sheet, which is:

<xsl:template match="CrossRefer开发者_如何转开发ence ">
     <xsl:variable name="currentNode" select="//*[@Target=@pointer]"/>
     <xsl:if test="$currentNode/name()!= 'Figure'">

            ...
      </xsl:if>
</xsl:template>

It always complains about the line, and the message is "An exception occurred while compiling the stylesheet: Unknown nodetype: name". Seems that it cannot understand the function name()?

Could anyone help? Thanks.

---

You cannot use a function call as part of a path (i.e. after a slash /) in XPath 1.x. To work around this the built-in XPath functions typically accept a node-set as their argument and default to . if the argument is omitted. That is, name() is shorthand for name(.).

Try this instead:

<xsl:if test="name($currentNode) != 'Figure'">