Here is my WSDL :
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://xxx" xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:ns0="http://xxx/commun/axis" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:tns="http://xxx" xmln开发者_Python百科s:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<wsdl:types>
<xsd:schema targetNamespace="http://xxx/commun/axis" xmlns="http://www.w3.org/2001/XMLSchema">
<xsd:include schemaLocation="https://host:port/path/WebServices/wsdl/typesServicesApplicatifs.xsd"/>
(...)
The typesServicesApplicatifs.xsd file is in the same directory as the WSDL file (inside a war), is it possible tu use a relative path instead of an absolute path for the schema location ?
It would be really helpful, because for now, the schemaLocation is different on each environnment (the host and the port have to be specified).
EDIT : this question is the same as the last one in this thread (with no answer) : http://forum.springsource.org/showthread.php?p=342542
Here is a way to achieve this :
Using Spring-WS, the WSDL can be generated automatically from :
<sws:dynamic-wsdl id="holiday" portTypeName="HumanResource" **locationUri="/holidayService/"** targetNamespace="http://mycompany.com/hr/definitions">
<sws:xsd location="/WEB-INF/hr.xsd"/>
</sws:dynamic-wsdl>
source : http://static.springsource.org/spring-ws/site/reference/html/tutorial.html#tutorial-publishing-wsdl
This way, the host, port and context path don't need to be specified inside the WSDL.
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