i've got this ugly jquery selectors..
$('div img').eq(3).css('padding-right', '0'); //multiple of 4...
$('div img').eq(7).css('padding-right', '0');
$('div img').eq(11).css('padding-right',开发者_如何学运维 '0');
$('div img').eq(15).css('padding-right', '0');
i have to get all imgages in positioned in 4^ and multiple-of-4 positions...
is there a better code than mine? :-)
Yes:
$('div img:nth-child(4n+3)').css('padding-right', '0');
You can use nth-child as illustrated here:
http://jsfiddle.net/YdsjY/
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