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Update elements by class in each Prototype selector result

开发者 https://www.devze.com 2022-12-13 20:07 出处:网络
Ok, so i have a HTML structure like this: <div class=\"content\"> <div id=\"a1\" class=\"article\">

Ok, so i have a HTML structure like this:

<div class="content">
  <div id="a1" class="article">
    <p>content</p>
    <p>content</p>
    <p class="info"></p>
  </div>
  <div id="a2" class="article"></div>
  <div id="a3" class="article"></div>
  <div id="a4" class="article"></div>
</div>

The goal is to process each article and add info about it into the info p element. So I figured I'd loop through all the divs like this:

$$('.article').each(function(item,index){
   var info = $(item).select('p.info');
   info.updat开发者_开发知识库e('<a>link</a> <p>Stuff about the article etc.</p>');
}); 

and write new content with update(). It does not work, however, the error being that .update() is not a function. How would I do the update?

OK, results: T.J. Crowder hinted why it wasn't working, and I eventually came up with this code:

$(item).select('p.info')[0].update('Stuff about the article etc.');

Key point was in manipulating the first item of array returned by the select(), which then updated the info element as i wanted it to..


Element#select returns an array, not an element, but you're treating it like an element. You might want Element#down instead.

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