Input matrix A
column1 column2 column3 column4
row1 0 1 0 0
row2 0 0 -1 0
row3 1 0 0 -1
Input matrix B
column5 column6 column7 column8
row1 0 1 0 0
row2 0 0 -1开发者_如何学C 0
row4 1 0 0 -1
Output matrix C
column1 column2 column3 column4 column5 column6 column7 column8
row1 0 1 0 0 0 1 0 0
row2 0 0 -1 0 0 0 -1 0
row3 1 0 0 -1 0 0 0 0
row4 0 0 0 0 1 0 0 -1
Remarks: matrix A and matrixB got overlapped row's name. However, all the columns' names are different.
You can use merge
to do this by specifying the optional parameters by
and all
:
#Reading data
txt1 <- "column1 column2 column3 column4
row1 0 1 0 0
row2 0 0 -1 0
row3 1 0 0 -1
"
txt2 <- "column5 column6 column7 column8
row1 0 1 0 0
row2 0 0 -1 0
row4 1 0 0 -1
"
dat1 <- read.table(textConnection(txt1), header = TRUE)
dat2 <- read.table(textConnection(txt2), header = TRUE)
#Merge them together
merge(dat1, dat2, by = "row.names", all = TRUE)
Will yield
Row.names column1 column2 column3 column4 column5 column6 column7 column8
1 row1 0 1 0 0 0 1 0 0
2 row2 0 0 -1 0 0 0 -1 0
3 row3 1 0 0 -1 NA NA NA NA
4 row4 NA NA NA NA 1 0 0 -1
If you want to replace the NAs with zeros, this should work:
#Assign to an object
zz <- merge(dat1, dat2, by = "row.names", all = TRUE)
#Replace NA's with zeros
zz[is.na(zz)] <- 0
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