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jQuery inverted selector given a list of values

开发者 https://www.devze.com 2023-02-27 05:04 出处:网络
I need to be able to remove elements based on a list.This has to be easy to do but I\'m not seeing the forest through the trees here.

I need to be able to remove elements based on a list. This has to be easy to do but I'm not seeing the forest through the trees here.

I want to pass in multiple values in a single list. Remove elements not in the list.

    <select id="productList">
    <option value="CD-6">6 M开发者_StackOverflow中文版onth CD 10K</option>
    <option value="CD-12">12 Month CD 10K</option>
    <option value="CD-24" selected="selected">24 Month CD 10K</option>
</select>

That is a static list. I want to leave lets say "CD-12, CD-24" and remove CD-6.

$("#productList option:not:contains('CD-12, CD-24')").remove();

Not working, anyone got an idea?


Using contains() is not a good idea, you should be testing the value attribute.

$("#productList option:not([value='CD-12']):not([value='CD-24'])").remove()


$("#productList option:not([value='CD-12'],[value='CD-24'])");

This works properly and gives the desired output. Only CD-12 and CD-24 remain in the listbox.

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