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Implementing stack in python by using lists as stacks [closed]

开发者 https://www.devze.com 2023-02-27 03:08 出处:网络
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical andcannot be reasonably answered in its current form. For help clari
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 11 years ago.

I am create a stack demo with some functionality:

( Method ) __init__(self, n) => How can I initial the fix  n len of stack. ?
( Method ) IsEmpty      => Done by using lists as stacks 
( Method ) IsFull       => Done by using lists as stacks 
( Method 开发者_C百科) Push         => Done by using lists as stacks 
( Method ) Pop          => Done by using lists as stacks 

The code i am doing

 class Stack(object) :

   def __init__(self) :
    self.items = []
   def push(self, item) :
    self.items.append(item)

   def pop(self) :
    return self.items.pop()

   def isEmpty(self) :
    return (self.items == []) 

if __name__ == "__main__":
    demoStack = Stack()
    demoStack.push(1)
    print demoStack.items

Anyboday know to do this?

thanks


Python's list probably already has everything you want. If you want some additional functionality like limiting max number of objects you should subclass it or wrap around it with another class.


Check out Using lists as stacks in python.


Python has it built-in, see Using Lists as Stacks. It sounds like you might benefit from the Python Tutorial, as well.


>>> stack = []
>>> print stack
[1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> val = stack.pop()
>>> print stack
[1, 2, 3, 4, 5, 6, 7, 8]
>>> val
9
>>> 
0

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