I have the following simple program to generate floating point random numbers between 1 and 4:
#include<stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
int i = 0;
float u;
srand((unsigned)time(NULL));
for(i = 0;i< 10000 ; i++)
{
u = ((4-1)*((float)rand()/RAND_MAX))+1;
printf("The random value for iteration = %d is %2.4f \n", i, u);
}
}
It succes开发者_运维知识库sfully generates floating point random numbers between 1 and 4 on an x86 Red Hat Linux machine. But the same program produces 0.0000 as random number on a PPC running Montavista Linux.
Could someone explain why and how to make this work on the PPC Montavista ?
A hunch is that you should be using double instead of float or printing (double)u
, since %f
takes a double. I was under the impression that floats were automatically promoted to double when passed to a vararg function though.
You could also try printing (int)(u*10000)
.
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