How can I compare two different dates to find out which is the later date? For example, in date1
I will store one date after downloading some data, and in date2
, I will store the current date. Then I need to check which one is greater/later: something like if(date1>date2)
.
Something like:
NSDate* timeNow = [NSDate date];
// If less than 30 seconds, do something
if ([timeNow timeIntervalSinceDate:anEarlierTime] < 30.0f)
{
// Do something
}
you can use NSDate's compare: method:
NSComparisonResult result = [Date2 compare:Date1];
if(result==NSOrderedAscending)
NSLog(@"Date1 is in the future");
else if(result==NSOrderedDescending)
NSLog(@"Date1 is in the past");
else
NSLog(@"Both dates are the same");
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"yyyy-MM-dd"];
NSDate *dt1 = [[NSDate alloc] init];
NSDate *dt2 = [[NSDate alloc] init];
dt1 = [df dateFromString:@"2011-02-25"];
dt2 = [df dateFromString:@"2011-03-25"];
NSComparisonResult result = [dt1 compare:dt2];
switch (result)
{
case NSOrderedAscending: NSLog(@"%@ is greater than %@", dt2, dt1); break;
case NSOrderedDescending: NSLog(@"%@ is less %@", dt2, dt1); break;
case NSOrderedSame: NSLog(@"%@ is equal to %@", dt2, dt1); break;
default: NSLog(@"erorr dates %@, %@", dt2, dt1); break;
}
This is what I used for comparing dates with timezones, and worked for me using iOS 6
NSComparisonResult result = [timeStamp compare:serverDate];
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"yyyy-MM-dd HH:mm:ss z"];
switch (result)
{
case NSOrderedAscending:
NSLog(@"%@ is greater than %@", [df stringFromDate:serverDate], [df stringFromDate:timeStamp]);
break;
case NSOrderedDescending:
NSLog(@"%@ is less %@", [df stringFromDate:serverDate], [df stringFromDate:timeStamp]);
break;
case NSOrderedSame:
NSLog(@"%@ is equal to %@", [df stringFromDate:serverDate], [df stringFromDate:timeStamp]);
break;
default:
NSLog(@"erorr dates %@, %@", [df stringFromDate:serverDate], [df stringFromDate:timeStamp]);
break;
}
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