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#define statement explained

开发者 https://www.devze.com 2022-12-13 19:26 出处:网络
gcc 4.4.1 I am maintaining someone\'s code and I have come across something that I don\'t understand. #define RES_API(name, func) name##_##func

gcc 4.4.1

I am maintaining someone's code and I have come across something that I don't understand.

#define RES_API(name, func) name##_##func

Can anyone e开发者_JS百科xplain?

Many thanks,


The ## is a concatenation operator. Using RES_API(name1, func1) in your code would be replaced with name1_func1. More information here.


The ## operator concatenates two tokens. In your case, name is appended with an underscore, and that is appended with func.

So RES_API(aName, aFunc) results in aName_aFunc.

By itself, it seems rather annoying. I could see a use when mixing C and C++ code, as C libraries tend to prefix their functions, while C++ libraries would place them in a namespace.

Given an alternate definition, such as:

#define RES_API(name, func) name##::##func

You suddenly have a generic way to switch between a C interface, or C++.


I know you've already got your answer, but there is some great info on the C-FAQ which explains allot of the C Preprocessor magic.


Instead of doing OBJ_DoSomething, with this macro you can do RES_API(OBJ, DoSomething). Personally I think its silly.

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