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Convert NSString(2011-04-18 18:57:47.453000) to NSDate

开发者 https://www.devze.com 2023-02-26 10:59 出处:网络
Hey, guys i 开发者_StackOverflow社区searched a lot but cant get my code working. I am getting a date in form of a string with format like : 2011-04-18 18:57:47.453000

Hey, guys i 开发者_StackOverflow社区searched a lot but cant get my code working.

I am getting a date in form of a string with format like : 2011-04-18 18:57:47.453000

I want to convert this to NSDate to calculate time elapsed, but I cant seem to get the conversion right. here is what i am doing:

NSString *dateString = [entityData objectForKey:@"creation_time"];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss.fff"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release];

when i print dateString i get : 2011-04-18 18:57:47.453000 but printing dateFromString gives: (null)

Can anyone point me in the right direction?


You probably solved this awhile ago... but:

NSString *dateString = @"2011-04-18 18:57:47.453000";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeZone: [NSTimeZone timeZoneWithAbbreviation:@"GMT"]];
[df setDateFormat:@"yyyy-MM-dd HH:mm:ss.SSSSSS"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [df dateFromString:dateString];
[df release];

Some good information on converting date components can be found in the "Date Field Symbol Table" located here:

http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns

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