How can I do the following in mysql开发者_如何转开发i prepare statement?
$result = mysql_query($sql);
$data = mysql_fetch_assoc($result);
return $data:
You need to use the MySQLi version of the functions:
$result = mysqli_query($sql);
$data = mysqli_fetch_assoc($result);
return $data;
That should do it, you also might want to take a look at:
- http://php.net/mysqli
- http://www.php.net/manual/en/class.mysqli-result.php
That's pretty simple after you've created the connection to mysql somewhere:
<?php
// create the connection to mysql.
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'my_db');
?>
The refer to the mysqli object when you need to do a query or do something else.
<?php
// get the result object.
$result = $mysqli->query($sql);
// fetch the result row.
$data = $result->fetch_assoc();
return $data;
?>
Then at some point (if you have a class, you can write a destructor) you should close the connection to mysql if you won't need it anymore.
<?php
$mysqli->kill($mysqli->thread_id);
$mysqli->close();
?>
You can do much more with the result object you have.
So read more about the MySQLi_Result
here:
- http://www.php.net/manual/en/class.mysqli-result.php
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