I have a web page in which I am giving USER the options of writing notes. Now when ever the web page checks that a USER is:abc then it pulls up the note from the MEMO Table.
Here is my code in Page_Load():
using (EntityMemoDataContext em = new EntityMemoDataContext())
{
int getEntity = Int16.Parse(Session["EntityIdSelected"].ToString());
开发者_运维知识库 var showMemo = from r in em.EntityMemoVs_1s
where r.EntityID == getEntity
select r.Memo;
tbShowNote.Text = String.Join(@"<br />", showMemo);
}
tbShowNote is showing me value like this:
test<br />test1<br />test1<br />test4<br />test4
And I want it like this:
Test
Test1 Test2 ...
tbShowNote is a TextBox!
You only asked for the first memo, so that's what you got back. If you want it enumerated with each one on it's own line in html, you could do this:
using (EntityMemoDataContext em = new EntityMemoDataContext())
{
int getEntity1 = Int16.Parse(Session["EntityIdSelected"].ToString());
var showMemo = from r in em.EntityMemoVs_1s
where r.EntityID == getEntity1
select new
{
r.Memo
};
tbShowNote.Text = String.Join(@"<br />", showMemo);
}
The key takeaway is if r.Memo is of type string, then the LINQ query you executed gave you back a IQueryable<string>
. It's on you to decide if you want to flatten that list later.
Edit: Equiso made a good observation in that you're actually returning an IQueryable
of an anonymous type, not IQueryable<string>
due to the new { ... }
syntax. I'd say combine his answer with mine and run with it:
var showMemo = from r in em.EntityMemoVs_1s
where r.EntityID == getEntity1
select r.Memo;
tbShowNote.Text = String.Join(@"<br />", showMemo);
The problem is in the select
part of your linq query, you are wrapping your results in an anonymous type, that is why when you call ToString()
you see { Memo = test }
. You probably want it like this:
var showMemo = from r in em.EntityMemoVs_1s
where r.EntityID == getEntity1
select r.Memo;
After that showMemo
will contain just strings.
It looks like your showMemo is a collection and you are then just assigning the top value? If you are putting them in one string then you need to aggregate them together.
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