I have write some code but my program is too slo开发者_JAVA技巧w. The problem is as follows:
I'll build Matrix "A" to solve Ax=b problem
I have a sphere(it may be any shape), that is showed by some point,
I have assigned a coordinate vector [x y z] for each point.
N is the number of points.
Please first load (a)
clc
[rv,N,d0]=geometrySphere(5e-9,10); %# Nx3 matrix [x1 y1 z1;x2 y2 z2;... ].
%# geometrySphere is a function for replacicg the sphere with points.
L=(301:500)*1e-9; K=2*pi./L; %# 1x200 array
%some constants ==================
I=eye(3);
e0=1;
V=N*d0^3; aeq=(3*V/(4*pi))^(1/3);
E0y=ones(N,1);
E0z=E0y;
Cext=zeros(1,200);
Qext=zeros(1,200);
A=zeros(3,3,N^2);
%=================================
for i=1:N
r(i)=sqrt(rv(i,1)^2+rv(i,2)^2+rv(i,3)^2); %# r is the size of each vector
end
for i=1:N
for j=1:N
dx(i,j)=rv(i,1)-rv(j,1); %# The x component of distance between each 2 point
dy(i,j)=rv(i,2)-rv(j,2);
dz(i,j)=rv(i,3)-rv(j,3);
end
end
d=cat(3,dx,dy,dz); %# d is the distance between each 2 point (a 3D matrix)
nd=sqrt(dx.^2+dy.^2+dz.^2); %# Norm of rv vector
nx=d(:,:,1)./nd; ny=d(:,:,2)./nd; nz=d(:,:,3)./nd;
n=cat(3,nx,ny,nz); %# Unit vectors for points that construct my sphere
for s=1:length(L)
E0x=exp(1i*K(s)*rv(:,1))';
% 1x200 array in direction of x(in Cartesian coordinate system)
% Main Loop =================================================
p=1;
for ii=1:N
for jj=1:N
if ii==jj
A(:,:,p)=a(s)*eye(3); %# 3x3 , a is a 1x200 constant array
p=p+1; %# p is only a counter
else
A(:,:,p)=-exp(1i*K(s)*nd(ii,jj))/nd(ii,jj)*(-K(s)^2*([nx(ii,jj);ny(ii,jj);nz(ii,jj)]...
*[nx(ii,jj) ny(ii,jj) nz(ii,jj)]-I)+(1/nd(ii,jj)^2-1i*K(s)/nd(ii,jj))...
*(3*[nx(ii,jj);ny(ii,jj);nz(ii,jj)]*[nx(ii,jj) ny(ii,jj) nz(ii,jj)]-I));
p=p+1;
end
end
end
%===============================================================
B = reshape(permute(reshape(A,3,3*N,[]),[2 1 3]),3*N,[]).';
%# concatenation of N^2 3x3 matrixes into a 3Nx3N matrix
for i=1:N
E00(:,i)=[E0x(i) E0y(i) E0z(i)]';
end
b=reshape(E00,3*N,1);
P=inv(B)*b;
Cext(s)=(4*pi*K(s))*imag(b'*P);
Qext(s)=Cext(s)/(pi*aeq^2);
end
Qmax=max(Qext); Qext=Qext/Qmax;
L=L*1e9;
plot(L,Qext,'--');figure(gcf)
I don't know could I explane clear?
Do you have any suggestion? Thanks in advance for any suggestions.
geometrySphere
Where I is the 3x3 identity matrix and nij nij denotes a dyadic product.(a) after running a function is:an 1x200 array
The first two loops can be easily replaced by the following vector operations (I haven't tested it):
r=sqrt(sum(rv,2).^2);
[npoints,ndims]=size(rv);
pairs=combnk(1:npoints,2);
npairs=size(pairs,1);
index=repmat(pairs(:),ndims,1)+npoints*reshape(repmat(0:ndims-1,npairs*2,1),npairs*2*ndims,1);
d=reshape(reshape(rv(index),npairs*ndims,2)*[1 -1]',npairs,ndims); %'
n=bsxfun(@rdivide,d,sqrt(sum(d.^2,2)));
Note that in your case, dx
, dy
and dz
will be skew-symmetric matrices with zero diagonals and hence only N(N-1)/2
independent elements. This pairing can be achieved by combnk
, which gives all possible pairs from n
items. Hence, the d
here is an N(N-1)/2x3
element array, whereas your d
is an NxNx3
array, yet contains the same information.
Now the main loop also looks like it can be vectorized, however its too long and I don't want to spend time going through all the indices. But here are some suggestions:
- You can do element-wise operations in MATLAB using a
.
prefix before the operator. So if you have two equi-dimensional arrays/vectors, likeA=[a b c]
andB=[d e f]
(assume real), the dot product of the two vectors is simplyA.*B
, which gives[ad be cf]
. Similar rules for division and raising it to a power. You can read more about it here. - You can do matrix multiplications using the
*
operator (no dot here), and the inner dimensions must match. So with the above example, the inner product is simplyA*B'
, which gives youad+be+cf
, and the outer product (dyadic product) isA'*B
, which gives you a3x3
matrix:[ad ae af;bd be bf;cd ce cf]
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