NSString stringWithFormat: with random number of replacements

I am reading in a list of strings, each of which can contain a number of placeholders (%@). I would like to use stringWithFormat: to insert the appropriate value but this works for only one substitution. What can I use to substitute all the values? Is there some sort of string substitutio开发者_开发技巧n function?

This is an example of what I am trying to do (a little bit of pseudo code):

NSString[] patterns = { "my name is %@ every day", "my name is %@ and it will remain %@" };
foreach (NSString s in patterns )
{
    // sometimes the string has one substitution, and sometimes
    // more. The project where I am doing this throws a BAD_ACCESS
    // error if more than one substitution is required so need
    // to take a different approach?
    print [NSString stringWithFormat:s, "Jack"];
}

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You can tell stringWithFormat: to use the same argument repeatedly by specifying the position. See String Format Specifiers. Example:

[NSString stringWithFormat:@"%1$@ is the first argument, and so is %1$@",@"this"];
// creates "this is the first argument, and so is this"

You could also use stringByReplacingOccurrencesOfString:withString: to replace all instances of "%@", but this requires that you do each argument separately and they must be strings:

[@"%@ is the first argument, and so is %@" stringByReplacingOccurrencesOfString:@"%@" withString:@"this"];