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How do I cast a double to an int?

开发者 https://www.devze.com 2023-02-24 09:44 出处:网络
I have a program that uses a formula to calculate the refurb on a unit (parts replaced on cableboxes that were damaged) divided by total units (cableboxes that went through refurb, but did not have an

I have a program that uses a formula to calculate the refurb on a unit (parts replaced on cableboxes that were damaged) divided by total units (cableboxes that went through refurb, but did not have any parts replaced). I looked up casting online, and the format for it is:

开发者_运维知识库
int valuetoconvert = Convert.ToInt32;

I'm doing that, but I still get the following error:

Cannot implicitly convert type 'double to int. An explicit conversion exists(are you missing a cast?)

What am I doing wrong? Can someone please help? Thank you.

Here's some of my code:

private int GetRefurbRate()
{
string sql = "";
double Refurb_Rate;
int totalRefurb = 0;
int totalUnits = 0;
string error_msg = "";


sql = "SELECT COUNT(rp.repair_ord) " +
"FROM " + schema + ".repair_part rp " +
"WHERE rp.repair_ord = '" + repair_ord + "' ";
while (true)
{
if (!myDb.RunSql(sql, true))
{
error_msg = "DBError for getting Refurb Rate";
break;
}
if (myDb.dbRdr.HasRows)
{
if (myDb.dbRdr.Read())
{
try //Try and Catch are here b/c I originally had everything ints, and and they just caught the 0 exception.
{

Refurb_Rate = Convert.ToInt32( totalRefurb / totalUnits * 100); //This is where I try to perform the cast.

}
catch (Exception e)
{
Console.WriteLine(e);
}

}

//int Refurb_Rate = Convert.ToInt32(Refurb_Rate);
}

break;
}
myDb.dbRdr.Close();

if (error_msg != String.Empty)
{
MessageBox.Show(error_msg, "Get Refurb Rate",
MessageBoxButtons.OK, MessageBoxIcon.Asterisk);
}


You say you want an int cast, but you actually need to cast to a double. You can do that like so (Example Code):

Refurb_Rate = (double)totalRefurb / (double)totalUnits * 100d;

Otherwise, you need to change Refurb_Rate from a double to an int.


You need to say that you want an int cast:

double a;
int b = (int) a;


I don't understand your error, because Refurb_Rate is a double and everything else is an int. However, I think what you really want is this:

if (totalUnits != 0)
    Refurb_Rate = totalRefurb * 100.0 / totalUnits;

Or possibly you want something like this:

int Refurb_Rate = 0;
...
if (totalUnits != 0)
    Refurb_Rate = totalRefurb * 100 / totalUnits;


Try this:

Refurb_Rate = (int)((double)totalRefurb / totalUnits * 100);

Make sure you case the int to double otherwise 1 / 2 will equal zero instead of .5

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