Regex - Every spaces without back on line

I would like to 开发者_Go百科accept any spaces with [\s] between to words, but not returns on the line -> [^\n].

I'm using

([\w\-]+)([\s[^\n]])([\w\-]+) 

but i doesn't work.

How can I do that?

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A character class within another character class will not work. It would be better to specify what you want to match. So [ \t]+ which means one or more spaces or tabs.

Two more points:
1. - does not need to be escaped in a character class if it is the first or the last character, so [\w-] or [-\w] will work fine.
2. Unless you want to use the white space characters between the words you do not need to use brackets.

In summary, the following should work fine:

([-\w]+)[ \t]+([-\w]+)

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try the following regex:

([\w\-]+)([\s^[\n]])([\w\-]+) 

That should add the "not" you want for new lines.

cheers!