Regex for non ANSI-style joins?

One of our rules is that all database joins have to be ANSI-style. As part of our build process I would like to scan all joins committed to source contro开发者_C百科l for violations.

I got a partial answer which I will post below but I'm sure its missing something and there must be a better one.

Here is a non-comprehensive list of examples

Should match:

SELECT * 
FROM cats, owners, dogs
WHERE cats.owner = onwers.id and owners.id += dogs.owner;


SELECT * FROM cats c, owners o WHERE c.owner = o.id;

Should not match:

SELECT *
FROM owners left outer join cats on (owners.id = cats.owner);

SELECT * 
   FROM owners inner join cats on (cats.owners = GetOnersOfTabbies(param1, parm2))

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Well, here I go:

FROM [\s\S]*?,[\s\S]*?WHERE

Will match a , between FROM and WHERE clauses even inside a multi line query.

[\s\S]*? means: take smallest possible match for whitespace characters (including line-breaks) and non-whitespaces; this is also known as "non-greedy pattern".

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Here's my regex:

from\s+\w+(\s+)?(\w+)?,(\s+)?\w+

Ruben's answer didn't work for me in my regex tester.

\s     == space character
\s+    == 1+ space character(s)
(\s+)? == Within the brackets is optional, reqires a "?" immediately after the ")"
\w     == word character, alphanumeric

To catch SELECT * FROM (cats c, owners o) WHERE c.owner = o.id;, use:

from\s+(\()?\w+(\s+)?(\w+)?,(\s+)?\w+

You need to escape the bracket, using the \ character:

(\()?  == '(' character

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Here is my attempt:

FROM (\s*\S+\s*(\w\s*)*,)+

Should pick up the first comma in a from clause - these are necessary for old style joins.