how to surround a word using System.Text.RegularExpressions.Regex

I've seen this topic: How to surround text with brackets using regex? but that's on ruby and I don't know the analog for C# I tried

text = System.Text.RegularExpressions.Regex.Replace(text, ' '  + SpecialWord + ' ', " \"\0\" ", System.Text.RegularExpressions.RegexOptions.IgnoreCase);

but that didn't insert my matched word. So how do I surround my matched word w开发者_StackOverflowith quotes?

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use $ instead of \ for the backreference. Also, put your special word in parenthesis and reference that sub group, otherwise, you will get the complete matched string:

text = System.Text.RegularExpressions.Regex.Replace(
                         text, "\\b("  + SpecialWord + ")\\b", " \"$1\" ", 
                         System.Text.RegularExpressions.RegexOptions.IgnoreCase);

Explanation:

• \b is a word boundary, i.e. a space, the end of the string, a full stop etc.
• $0 will match the whole match, i.e. including the word boundary, whereas $1 matches the first sub group, i.e. the part in the parenthesis.

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Try using \b to match the word boundary, rather than a space.

You need to use $0 instead of \0 too.

text = Regex.Replace(text, @"\b" + SpecialWord + @"\b", @" ""$0"" ", RegexOptions.IgnoreCase);