I've got 3 ta开发者_开发技巧bles:
- users (id, name, ...)
- items (id, name, ...)
- downloads (user_id, item_id, ...)
How do I get all users together with the number of downloads they have?
How do I get all users together with the number of downloads they have?
Use:
SELECT u.name,
COUNT(d.user_id) 'num_downloaded'
FROM USERS u
OIN DOWNLOADS d ON d.user_id = u.user_id
GROUP BY u.name
If you want to see how many times a user has downloaded a specific item:
SELECT u.name 'user_name',
i.name 'item_name',
COUNT(d.user_id) 'num_downloaded'
FROM USERS u
JOIN DOWNLOADS d ON d.user_id = u.user_id
JOIN ITEMS i ON i.item_id = d.item_id
GROUP BY u.name, i.name
This should do it:
SELECT u.name as name, count(*) as downloads
FROM users u, items i, downloads d
WHERE u.id = i.user_id AND i.user_id = d.user_id;
I had to invent items.user_id
, but it should be available.
精彩评论