SHOW TABLES statement with multiple LIKE values

mysql> SHOW TA开发者_JS百科BLES like 'cms';
+-------------------------+
| Tables_in_tianyan (cms) |
+-------------------------+
| cms                     |
+-------------------------+
1 row in set (0.00 sec)

Result

mysql> SHOW TABLES like 'cms' or like 'role';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual...

How can I filter by multiple conditions ?

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You need to use the WHERE clause. As shown in the docs, you can only have a single pattern if you use "SHOW TABLES LIKE ...", but you can use an expression in the WHERE clause if you use "SHOW TABLES WHERE ...". Since you want an expression, you need to use the WHERE clause.

SHOW TABLES
FROM `<yourdbname>`
WHERE 
    `Tables_in_<yourdbname>` LIKE '%cms%'
    OR `Tables_in_<yourdbname>` LIKE '%role%';

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You can just use a normal SQL WHERE statement to do it.

SHOW TABLES WHERE Tables_in_tianyan LIKE '%cms%'

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show tables from mydb 
where 
  Tables_in_mydb like '%statistics%' 
  or Tables_in_mydb like '%device%';

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You take table list using the below code

select TABLE_NAME from information_schema.TABLES where TABLE_SCHEMA = 'database_name' 

Hope it will help you.

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this will help

SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME LIKE 'cms%';